Question

What is the derivative of `f(t) = (t^3-e^(3t-1) , 3t^2+2e^t )`?

Answer 1

`dy/dx=(6t+2e^t)/(3t^2-3e^(3t-1))`

Explanation:

`x'(t)=3t^2-3e^(3t-1)`
`y'(t)=6t+2e^t`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(6t+2e^t)/(3t^2-3e^(3t-1))`