Question

What is the derivative of `f(t) = (1-e^t , sec(1-t) )`?

Answer 1

`f'(t)=(sec(1-t)tan(1-t))/(e^t)`

Explanation:

`x'(t)=-e^t`
`y'(t)=-sec(1-t)tan(1-t)`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(-sec(1-t)tan(1-t))/(-e^t)=(sec(1-t)tan(1-t))/(e^t)`