How do you factor completely #x^3 - 4x^2 + 4x - 16#?
1 Answer
Dec 31, 2015
Factor by grouping to find:
#x^3-4x^2+4x-16=(x^2+4)(x-4)#
Explanation:
#x^3-4x^2+4x-16#
#=(x^3-4x^2)+(4x-16)#
#=x^2(x-4)+4(x-4)#
#=(x^2+4)(x-4)#
If we allow Complex coefficients...
#=(x-2i)(x+2i)(x-4)#
