Question

What is the derivative of `f(t) = (t +te^t, e^t-t^2+t )`?

Answer 1

`f'(t)=(e^t-2t+1)/(1+e^t+te^t)`

Explanation:

`x'(t)=1+e^t+te^t`
`y'(t)=e^t-2t+1`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(e^t-2t+1)/(1+e^t+te^t)`