Question

How do you differentiate the following parametric equation: `(t-5t^3,3t^4-t^3)`?

Answer 1

`dy/dx=(12t^3-3t^2)/(1-15t^2)`

Explanation:

`x'(t)=1-15t^2`
`y'(t)=12t^3-3t^2`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(12t^3-3t^2)/(1-15t^2)`