What is the period of #f(t)=sin( ( t)/4 )#?

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Answer 1 · 2015-12-31T10:39:35

Period #= 8pi# step by step explanation is given below.

Period of #sin(Bx)# is given by #(2pi)/B#

#f(t) = sin(t/4)#

#f(t) = sin(1/4t)#

Comparing with #sin(Bx)# we can see #B=1/4#

Period is #(2pi)/B#

Here we get the period #=(2pi)/(1/4)#

Period #= 8pi#