Question

How do you find the amplitude, period, and shift for `y = -2sin (2x-3/2)?`?

Answer 1

#amplitude = 2, period = pi , shift = 3/2 to the right.

Explanation:

`a sin ( bx + c )` defines the sine waveform
a represents the amplitude in this case a = 2 (the - means that the graph will be reflected in the x-axis)
the period of `sinx is 2pi radians`
the period of `sin2x = 2pi/2 = pi` ie period = `2pi/b`

c denotes shift +c shifts c units left and -c c units to the right

hence c = 3/2 units to the right