Question

If a projectile is shot at an angle of `pi/6` and at a velocity of `23 m/s`, when will it reach its maximum height??

Answer 1

`h=6.747m`

Explanation:

Data:-
Angle`=theta=pi/6`
Initial Velocity`=`Muzzle Velocity`=v_0=23m/s`
Acceleration due to gravity`=g=9.8m/s^2`
Maximum Height`=h=??`

Sol:-
We know that:
`h=(v_0^2sin^2theta)/(2g)`
`implies h=(23^2*sin^2(pi/6))/(2*9.8)=(529*0.25)/19.6=132.25/19.6=6.747m`
`implies h=6.747m`