Question

What is the vertex of `y=x^2+3x+5`?

Answer 1

`Vertex (-3/2, 11/4)`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = -3/2`
y-coordinate of vertex:
`y(-3/2) = (9/4) + 3(-3/2) + 5 = 9/4 - 9/2 + 5 = 11/4`

`Vertex (-3/2, 11/4)`