Question

What is the electric current produced when a voltage of `8 V` is applied to a circuit with a resistance of `16 Omega`?

Answer 1

`I=0.5 A= 500 mA`

Explanation:

The Ohm's Rule is:

`R=V/I`

`:.I=V/R`

In this case:

`V= 8 V`
`R=16 Omega`

then

`I= cancel(8)^1/cancel(16)^2=1/2=0.5 A`

With A= Ampere measurement unit of I

Sometimes, in Electronic, is usally expressed as `[mA]`

`1mA=10^-3A`

`:.I=0.5 A= 500 mA`