Question

An object with a mass of `6 kg` is revolving around a point at a distance of `8 m`. If the object is making revolutions at a frequency of `9 Hz`, what is the centripetal force acting on the object?

Answer 1

`F=1.535xx10^5color(white)(x)"N"`

Explanation:

`f=9"Hz"`

This means the time period, i.e the time for 1 revolution is given by:

`T=1/f=1/9"s"`

Speed = distance travelled / time taken so:

`v=(2pir)/T=(2pi8)/(1/9)=144picolor(white)x"m/s"`

The expression for centripetal force is given by:

`F=(mv^2)/r`

`:.F=(6xx(144pi)^2)/8=1.535xx10^5color(white)(x)"N"`