An object with a mass of 6 kg is revolving around a point at a distance of 8 m. If the object is making revolutions at a frequency of 9 Hz, what is the centripetal force acting on the object?

1 Answer
Jan 15, 2016

F=1.535xx10^5color(white)(x)"N"

Explanation:

f=9"Hz"

This means the time period, i.e the time for 1 revolution is given by:

T=1/f=1/9"s"

Speed = distance travelled / time taken so:

v=(2pir)/T=(2pi8)/(1/9)=144picolor(white)x"m/s"

The expression for centripetal force is given by:

F=(mv^2)/r

:.F=(6xx(144pi)^2)/8=1.535xx10^5color(white)(x)"N"