Question

An object with a mass of `5 kg` is revolving around a point at a distance of `3 m`. If the object is making revolutions at a frequency of `17 Hz`, what is the centripetal force acting on the object?

Answer 1

`1.712xx10^5"N"`

Explanation:

The time period `T` for 1 revolution `=1/f=1/17s`

`v=d/T=(2pir)/T=(2pi3)/(1/17)=320.84"m/s"`

The centripetal force is given by:

`F=(mv^2)/r=(5xx320.84^2)/3=1.712xx10^5"N"`