Question

How do you find the slope and intercept of `4x-2y=12`?

Answer 1

`m=2`
`a=-6`
`b=3`

Explanation:

Given equation is `4x-2y=12`
Now, general slope equation is `y-y_o=m(x-x_o)` where `m` is the slope of the equation.
IF we rearrange the given equation, we see that it becomes
`2y=4x-12`
Considering `y_o=0`, and taking `4` common in the left hand side and dividing the whole equation by 2, we get what we want. That is
`2y=4(x-3)` Divide by `2` and
`y=2(x-3)`.
Comparing the one we solved with the general equation, we see that `m=2`.

Now, for intercept form equation, the general equation is
`y/a=x/b=1` where `a` is the y-intercept and `b` is the x-intercept.
So rearranging the original equation we had `4x-2y=12` and dividing the equation by `12`, we get
`x/3-y/6=1`
So `a=-6` (since the `y` parameter has a negative value)
and `b-3`