Question

The sum of three consecutive odd integers is 99. What are the three numbers?

Answer 1

I found `31,33,35`

Explanation:

Let us call our odd integers:
`2n+1`
`2n+3`
`2n+5`
and write our condition as:
`(2n+1)+(2n+3)+(2n+5)=99` and solve it for `n`:
`6n+9=99`
`6n=90`
`n=90/6=15`
so our numbers will be:
`2n+1=31`
`2n+3=33`
`2n+5=35`