Question

How would you graph `f(x)= 2 ln x`?

Answer 1

See the explanantion

Explanation:

To find the x-intercept mathematically

If `y=2ln(x)` then `ln(x)=y/2`

Another way of writing this is:

`e^(y/2)=x`.......................................(1)

The x-intercept is when `y=0` so equation (1) becomes:

`e^(0/2)=e^0=1=x`

So the x-intercept is at `x=1`
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You asked 'how' would you graph ....

The method would be to build a table of values.
The top row would have the values of x
The next row down would have the values of ln(x)
and the row below that would have the values of `2xxln(x)`

This last row gives the values for `y`

You would then mark a series of points that maches both your value of `x` and the calculated value of `y`

Your graph should look something like this: