How do you divide #(3x^3+2x^2-2x+4)/(x-3)#?

1 Answer
Alan P.
Jan 22, 2016

The fastest (and perhaps easiest) way is by synthetic division, to obtain:
#color(white)("XXX")3x^2+11x+3# with remainder #97/(x-3)#

Explanation:

synthetic division

#{: (,,x^3,x^2,x,), (,"|",3,2,-2,4), (,"|",,9,33,93), ("-----",,"-----","-----","-----","-----"), (xx(+3),"|",3,11,32,97), (,,x^2,x,,"Remainder") :}#

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