Question

An object with a mass of `6 kg` is revolving around a point at a distance of `2 m`. If the object is making revolutions at a frequency of `15 Hz`, what is the centripetal force acting on the object?

Answer 1

`108pi^2color(white)(x)"N"`

Explanation:

Centripetal force is given by:

`F=(mv^2)/r`

To find `v:`

`f=15"Hz"`

So the time period `T` is given by:

`T=1/f=1/15s`

`:.v=(2pir)/(1/15)=30pir`

`:.F=(6xx(3pir)^2)/r`

`F=(6xx9pi^2r^(cancel2))/cancel(r)`

`F=54pi^(2)xx2=108pi^(2)color(white)(x)"N"`