Question

A triangle has sides A, B, and C. Sides A and B are of lengths `6` and `5`, respectively, and the angle between A and B is `(pi)/2`. What is the length of side C?

Answer 1

side `c=sqrt 61=7.81025` units

Explanation:

Given data side `a=6` and side `b=5`, angle `C=pi/2`
By the Law of Cosines

`c=sqrt(a^2+b^2-2*a*b*cos C)`
`c=sqrt(6^2+5^2-2*6*5*cos (pi/2))`
`c=sqrt(36+25-0)`
`c=sqrt(61)`
`c=7.81025`

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