Question

What is the period of `f(theta)= sin 3 t - cos 5 t`?

Answer 1

period `= 2pi`

Explanation:

`f(t)=sin 3t-cos 5t`

for `sin 3t` the period `p_1`

`p_1=(2pi)/3=(10pi)/15`

for `cos 5t` the period `p_2`

`p_2=(2pi)/5=(6pi)/15`

Another number which can be divided by both `p_1` or `p_2` is `(30pi)/15`

Also `(30pi)/15=2pi`

therefore the period is `2pi`