How do you find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 34?

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Answer 1 · 2016-01-23T12:04:41

Set up an equation to find the integers to be
#3, 5, 7#

Let #n# be the least of the integers. Then the second is #n+2# and the third is #n+4#, so we have

#n + 2(n+2) + 3(n+4) = 34#

#=> n + 2n + 4 + 3n + 12 = 34#

#=> 6n + 16 = 34#

#=> 6n = 18#

#=> n = 3#

Thus the integers are #3, 5, 7#