Question

What is the angular momentum of an object with a mass of `7 kg` that moves along a circular path of radius `12 m` at a frequency of `2/3 Hz`?

I

Answer 1

`L=1344\piNs^-1`

Explanation:

Angular momentum of an object is `L=mvr`

Given that `m=7kg`, `r=12m` and `\omega=4\pi^c/3` (They had given us linear frequency, not angular frequency)

They haven't given us `v` directly. But, we know that `v=\omegar`, so let's get that into the angular momentum equation, which means
`L=m\omegar^2`

I'm sure you'll now understand how I got that `\pi` there in the answer now.