Question

The sum of 4 consecutive odd integers is 336, how do you find the largest integer?

Answer 1

I found `87`

Explanation:

Let us call the numbers:
`2n+1`
`2n+3`
`2n+5`
`2n+7`
We then can write:
`(2n+1)+(2n+3)+(2n+5)+(2n+7)=336`

rearranging and solving for `n`:

`8n+16=336`

`n=320/8=40`

The largest integer will be:

`2n+7=87`