How do you simplify the product #(3y + 7)(4y + 5)# and write it in standard form?
1 Answer
Jan 30, 2016
# 12y^2 + 43 y + 35#
Explanation:
Each term in the 2nd bracket must be multiplied by each term
in the 1st bracket,
The way to do this is 3y (4y + 5 ) + 7 (4y + 5 )
# = 12y^2 + 15y + 28y + 35 # simplifying to :
# 12y^2 + 43 y + 35#
