How do you solve #3sqrt(w + 1 )= 6#?

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Answer 1 · 2016-01-31T06:21:22

#w=3#

#3sqrt(w+1)=6#

#rarrsqrt(w+1)=6/3#

#rarrsqrt(w+1)=2#

Square both sides

#rarr(sqrt(w+1))^2=2^2#

#rarrw+1=4#

#rarrw=4-1=3#