How do you factor #27x³ - 64y³#?
1 Answer
Jan 31, 2016
# (3x - 4y )(9x^2 + 12xy +16y^2 ) #
Explanation:
This is a difference of 2 cubes which can be factorised as
# a^3 - b^3 = (a - b )(a^2 + ab + b^2 ) # for
# 27x^3 - 64y^3 , a = 3x color(black)(" and ") b = 4y # substituting these into the above expression to obtain
# 27x^3 - 64y^3 = (3x - 4y )( 9x^2 + 12xy + 16y^2 ) #
