Question

How do you write the slope-intercept form of the line with a slope of -2 and going through the point (3, 2)?

Answer 1

`y=-2x+8`

Explanation:

Given a slope of `m=-2` through the point `(barx,bary)=(3,2)`
we can write the linear equation in slope-point form as
`color(white)("XXX")y-bary=m(x-barx)`

`color(white)("XXX")y-2 =(-2)(x-3)`

We have been asked to convert this into slope-intercept form:
`color(white)("XXX")y=mx+b`

Simplifying the right side of our slope-point form:
`color(white)("XXX")y-2 = -2x+6`

Adding `2` to both sides to isolate the `y`
`color(white)("XXX")y=-2x+8`
`color(white)("XXXXXXXXXXX")`which is in the slope-intercept form