Question

A projectile is shot from the ground at a velocity of `11 m/s` at an angle of `pi/6`. How long will it take for the projectile to land?

Answer 1

`x_m=color(red)(6,5). color(green)(1,942)=12,623 m`

Explanation:

`v_(ix)=v_i. cos theta`
`v_(ix)=11. cos (cancel(pi)/6 *180/cancel(pi))`
`v_(ix)=11. cos 60`
`v_(ix)=11.0,5=6,5 m/s`
`color(red)(v_(ix)=6,5 m/s" initial velocity x component")`

`t_e=(2.v_i sin theta)/g`
`t_e=(2.11.sin 60)/g`
`t_e=(22. 0,866)/(9,81)`
`color(green)(t_e=1,942 s" elapsed time")`
`x_m=v_(ix). t_e`
`x_m=color(red)(6,5). color(green)(1,942)=12,623 m`