Question

How do you find an equation of hyperbola with given endpoints of the transverse axis: (0,-6),(0,6); Asymptote: y=3/10 x?

Answer 1

`y^2/36 - x^2/400 = 1`

Explanation:

Equation of parabola and asymptote
1) `y^2/a^2 - x^2/b^2 = 1`
2) `y = +- a/bx`
3) `a = 6; y = 3/10x; 3/10 = 6/b; b = 20`
Now substitute:
`y^2/36 - x^2/400 = 1`