Question

A projectile is shot from the ground at a velocity of `18 m/s` and at an angle of `(2pi)/3`. How long will it take for the projectile to land?

Answer 1

`t~=3,18 s`

Explanation:

`t=(2*v_i*sin alpha)/(g) " elapsed time"`
`alpha=(2pi)/3*180/pi=120^o`
`sin 120^o=sin 60^o~=0,866`
`t=(2*18*0,866)/(9,81)`
`t~=3,18 s`