Question

What is the distance between `(3, –1, 1)` and #(–4, 0, 2) #?

Answer 1

We must calculate distance as the usual way, using generalized Pythagoras theorem.

Explanation:

For generalized Pythagoras theorem, we have:

`d^2 = (x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2`

where `(x_1, y_1, z_1)` and `(x_2, y_2, z_2)` are both points.

Hence:
`d^2 = (-4-3)^2+(0-(-1))^2+(2-1)^2 = 51`

And taking square roots:
`d = sqrt{51}`