Question

An object with a mass of `6 kg` is revolving around a point at a distance of `8 m`. If the object is making revolutions at a frequency of `1 Hz`, what is the centripetal force acting on the object?

Answer 1

`F=momega^2r=6*(2pi)^2*8=1895` `N`.

Explanation:

In a linear frame the centripetal force is described as `F=(mv^2)/r` and in a rotational frame as `F=momega^2r` where `omega` is measured in radians.

`1` `Hz` is `2pi` `rads^-1`, so `F=6*(2pi)^2*8=1895` `N`.