Question

An object with a mass of `2 kg` is revolving around a point at a distance of `4 m`. If the object is making revolutions at a frequency of `5 Hz`, what is the centripetal force acting on the object?

Answer 1

`F=1600*pi^2N`

Explanation:

`"you can use the Newton's second law"`
`F=m*a`
`"change linear acceleration to rotary acceleration"`
`a=v^2/r ; v=omega*r ; v^2=omega^2*r^2`
`a=omega^2*r`
`F=m*omega^2*r`
`F=m*(2*pi*f)^2*r`
`F=4*4*pi^2*25*4`
`F=4^3*5^2*pi^2`
`F=64*25*pi^2`
`F=1600*pi^2N`