Question

An object with a mass of `5` `kg` is revolving around a point at a distance of `3` `m`. If the object is making revolutions at a frequency of `13` `Hz`, what is the centripetal force acting on the object?

Answer 1

The centripetal force is given by `F=momega^2r` where `m` is the mass `(kg)`, `omega` is the frequency `(rads^-1)` and `r` is the radius `(m)`.

`F=momega^2r=5*94.25^2*3=133246` `N`

Explanation:

We need to convert the frequency: `15` `Hz=30pi=94.25` rads^-1#.