Question

If `12 L` of a gas at room temperature exerts a pressure of `4 kPa` on its container, what pressure will the gas exert if the container's volume changes to `7 L`?

Answer 1

Pressure of gas will be `6.857` kPa.

Explanation:

As at constant temperature, if Pressure is `P`) and Volume is `V`, their product i.e. `P*V` is always constant.

Here 12L of a gas at room temperature exerts a pressure of 4kPa. Hence their multiplication is 48 and if container's volume changes to 7L. pressure of gas exerted on container will become `48/7=6.857` kPa.