How do you graph #sqrt(ln x) #?

1 Answer
Feb 16, 2016

See the graph drawn below

Explanation:

  1. #ln0# is undefined. It's not a real number, because you can never get zero by raising anything to the power of anything else.

  2. Also, function #lnx# is negative for all values of #x<1#, as square root of given function is real only for #x>=0#.

  3. Hence point #(1,0)# lies on the graph and the graph does not exist for all values of #x<1#

  4. Graph increases as square root of a logarithmic for all positive values of #x#

graph{y=(ln x)^(1/2) [-0.35, 9.104, -0.55, 4.18]}