How do you factor the expression $40 p^{2} - 13 p - 36$ $40p^2-13p-36$ ?

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How do you factor the expression $40 p^{2} - 13 p - 36$ $40p^2-13p-36$ ?

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Answer 1 · 2016-02-16T18:04:15

It is $(5 p + 4) (8 p - 9)$ $(5p+4)(8p-9)$

Explanation:

You can factor this as follows just remember that $13 = 45 - 32$ $13=45-32$ hence
we have that

$40 p^{2} - (45 - 32) \cdot p - 36 = 40 p^{2} - 45 \cdot p + 32 \cdot p - 36 = 5 p \cdot (8 p - 9) + 4 \cdot (8 p - 9) = (5 p + 4) \cdot (8 \cdot p - 9)$ $40p^2-(45-32)*p-36=40p^2-45*p+32*p-36= 5p*(8p-9)+4*(8p-9)=(5p+4)*(8*p-9)$

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How do you factor the expression $40 p^{2} - 13 p - 36$ $40p^2-13p-36$ ?

1 Answer

Explanation:

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How do you factor the expression 40p^2-13p-3640p2−13p−3640p^2-13p-36?

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How do you factor the expression $40 p^{2} - 13 p - 36$ $40p^2-13p-36$ ?