Question

How do you solve for a in `(10ac-x)/ 11 = -3`?

Answer 1

This is just standard algebra, but the answer will be expressed in terms of `c` and `x`. See below for the full calculation. `a=(x-33)/(10c)`

Explanation:

Starting equation. Our goal is to get `a` 'naked'. ;)

`(10ac-x)/11=-3`

Multiply both sides by 11:

`10ac-x=-33`

Add `x` to both sides:

`10ac=x-33`

Divide both sides by `10c`:

`a=(x-33)/(10c)`

And there's your answer.