Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `36 J` to `12 J`, what is the voltage between points A and B?

Answer 1

`V_(AB)=-8V`

Explanation:

`Delta W=q*(V_B-V_A)`
`V_(AB)=V_B-V_A`
`12-36=6*V_(AB)`
`-24=6*V_(AB)`
`V_(AB)=-24/6`
`V_(AB)=-8V`