Question

A charge of `2 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `28 J` to `14 J`, what is the voltage between points A and B?

Answer 1

`v_(AB)=-7 " V"`

Explanation:

`Delta W=q(V_B-V_A)`
`V_B_V_A=V_(AB)`
`Delta W=q*V_(AB)`
`14-28=2*V_(AB)`
`-14=2*V_(AB)`
`v_(AB)=-7 " V"`