Question

An object with a mass of `6 kg` is on a surface with a kinetic friction coefficient of `8`. How much force is necessary to accelerate the object horizontally at `9 m/s^2`?

Answer 1

`F=524,88N`

Explanation:

`F_f=u_k*m*g" Friction Force"`
`F_n=F-F_f" Net Force"`
`F_n=m*a`
`F-F_f=m*a`
`F-u_k.m*g=m*a`
`u_k=8 ; a=9 m/s^2 ; m=6 kg`
`F-8*6*9,81=6*9`
`F=54+8*6*9,81`
`F=524,88N`