Question

What is the period of `f(theta) = tan ( ( theta)/9)- sec ( ( 7theta)/ 6)`?

Answer 1

`(108pi)/7`

Explanation:

Period of tan x -->`pi`
Period of `tan (x/9) --> 9pi`
Period of `sec ((7x) /6)` = Period of `cos ((7x)/6)`
Period of `cos ((7x)/6) -> (12pi)/7`
Least multiple of `(9pi) and (12pi)/7` --> `9pi(12/7)` --> `(108pi)/7`
Period of `f(x) --> (108pi)/7`