How do you simplify #(3 + 2i)(2 + 4i)#?
1 Answer
Feb 25, 2016
Explanation:
distribute the brackets using FOIL , or any method you use .
#(3+2i)(2+4i) = 6 + 12i + 4i +8i^2# [ Note :
#i^2 =(sqrt-1)^2 = -1 # ]hence
#6 +12i + 4i + 8i^2 = 6 + 16i - 8 = -2 + 16i#