Question

The gas inside of a container exerts `42 Pa` of pressure and is at a temperature of `270 ^o K`. If the pressure in the container changes to `72 Pa` with no change in the container's volume, what is the new temperature of the gas?

Answer 1

New temperature is `462.86^oK`

Explanation:

As there is no change in Volume `V`, `P/T` is always constant, where `p` is Pressure and `T` is Temperature in degree Kelvin.

As initially container exerts `42Pa` of pressure and is at a temperature of `270^oK`, `P/T=42/270`. As pressure in the container changes to `72Pa`, if Temperature changes to `T_1`

`72/T_1=42/270`

Hence `T_1=(72*270)/42=462.86^oK`