Question

The gas inside of a container exerts `15 Pa` of pressure and is at a temperature of `220 ^o K`. If the temperature of the gas changes to `20 ^oC` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`19.9875 Pa`

Explanation:

As there is no change in Volume `V`, `P/T` is always constant, where `P` is Pressure and `T` is Temperature in degree Kelvin.

As initially container exerts `15Pa` of pressure and is at a temperature of `220^oK`, `P/T=15/220`.

As temperature of the container changes to `20^oC` i.e. `(20+273.15)^oK` i.e. `293.15^oK`, if Pressure changes to `P_1`

`P_1/293.15=15/220`

Hence `T_1=(15xx293.15)/220=19.9875 Pa`