How do you solve for x in #m^2x-3m^2=12m^2#?
1 Answer
Feb 26, 2016
Explanation:
There are a couple ways to do this; here is one:
#m^2x-3m^2=12m^2#
#rarr cancel(m^2)(x-3) = 12cancel(m^2)#
#rarr x=15#