An object with a mass of # 12 kg# is lying still on a surface and is compressing a horizontal spring by #3/2 m#. If the spring's constant is # 6 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2016-02-28T05:29:12

#\mu_s=0.0765#

Given that #m=12kg#, #k=6kgs^-2#, #deltax=3/2m#

The object is said to be lying still and hence the normal force times the coefficient of friction is the maximum restoring force applied on the body.

So, #kx=\mu_smg\impliescancel{6}^1*3/cancel{2}^1=\mu_s*9.8*cancel{12}^4#
So, #\mu_s=3/(4*9.8)#

I reduced the value up in the answer part.