How do you factor $- x^{2} - x + 6$ $-x^2 - x + 6$ ?

Question

1052 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-28T06:26:48

$(x + 3) & (x - 2)$ $(x+3) & (x-2)$

$- x^{2} - x + 6$ $-x^2-x+6$

$x^{2} + x - 6$ $x^2+x-6$

$x^{2} + 3 x - 2 x - 6$ $x^2+3x-2x-6$

$x (x + 3) - 2 (x + 3)$ $x(x+3)-2(x+3)$

$(x + 3) (x - 2)$ $(x+3)(x-2)$

Factors of above equation are $(x + 3) & (x - 2)$ $(x+3) & (x-2)$

How do you factor −x2−x+6-x^2 - x + 6?