Question

How do you factor `w^3-27`?

Answer 1

`w^3-27=(w-3)(w^2+3w+9)`

Explanation:

Use the formula for "difference of 2 cubes"

`a^3-b^3=(a-b)(a^2+ab+b^2)`

Let `a=w` and `b=3`
because `a^3=w^3` and `b^3=3^3=27`

then

`w^3-27=(w-3)(w^2+3w+9)`

God bless....I hope the explanation is useful..