How do you find the amplitude and period of a function #y=3sin(1/3x+ pi/2)-2#?

1 Answer
Feb 28, 2016

3 and 6#pi#.

Explanation:

The amplitude and period of the sine wave y = a sin (bx + c ) + d are a and 2#pi#/b.
Here, one full wave wave passes through
( 0, 1 ), ( #pi# , #-#1/2 ), (2#pi#, #-#7/2), ( 3#pi#, #-#5), (4#pi#, #-#7/2 ), (5#pi#, #-#1/2 ) and (6#pi#, 1 ).
Max y = 1 and min y = #-#5.
The wave is contained between the tangents y =1 and y = #-#5