What is the vertex of #y=5x^2-30x+49 #? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Tony B Mar 2, 2016 #x_("vertex")=3" "# I have left the determination of #y_("vertex")# for you to do (substitution). Explanation: Write as:#" "y=5(x^2-30/5x)+49# #x_("vertex") = (-1/2)xx(-30/5) = +3# To determine #y_("vertex")# substitute for #x# in the equation I will let you do that. Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 1723 views around the world You can reuse this answer Creative Commons License